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#atomic #incomplete #stub sourced from KBx2AExercises
1 Direct sums
Don't have the same rules when you add two together and many together! Intersection of zero != direct sum when you are adding more than one.
$ u1 + u2 + … + un = {u1+u2 + … + un \mid u1 ∈ U1 , … , un ∈ Un} $
If the direct sum requirements are not true, then it's just a sum.
Direct sum is all possible combos?
When all the vectors inside the direct sum are linearly dependent, then you can't make a direct sum with them? Because really, \(u_1 \in u_2\) Because the sums will not be unique. Redundancy!
$ U1 = {
\begin{bmatrix} 1 \\ 0 \end{bmatrix}} $ $ U2 = {
\begin{bmatrix} 2 \\ 0 \end{bmatrix}} $ doesn't work, cus you can just multiply all in \(U_1\) by 2 to get things in \(U_2\)