TR3.5

Chapter 3B Reading

Huxley Marvit 2021-11-08 Mon 09:59

#flo #hw


1 Null Spaces and Ranges

Two subspaces that are connected with every linear map

The set of vectors that get mapped to 0 is called the

title: null space, null T, AKA kernel
for $T \in$ [[file:KBxL(VcmW).org][KBxL(VcmW)]], the *null space* of $T$, denoted null $T$, is the subset of $V$ consisting of those vectors that $T$ maps to 0:
$$ 
null\ T = {v \in V : Tv = 0}. 
$$

1.0.1 examples of null space

  • The zero map! ie, \(Tv=0\) then \(\textrm{null}\ T = V\)
  • \(D \in L(P(R), P(R))\) where \(Dp=p'\), then the constant funcs are gonna go to 0.
    • ie. null space of \(D\) equals the set of constant functions.
  • backwards shift by one, \(\textrm{null}\ T = {(a, 0,0,...)}\)
  • null space of each linear transformation is a subspace of the domain?
    • ie, the kernel is a subspace.. oh boy

1.0.2 as a subspace

title: the null space is a subspace
Suppose $T \in L(V,W)$. Then $\textrm{null}\ T$ is a subspace of $V$

trivial proof, just plug in zeros.

ooh, and now we get,

1.0.3 injective

title: injective
a function $T: V \to W$ is called *injective* if $Tu = Tv$ implies $u=v$

#question what does "implies" mean here?

he calls this, one-to-one, but this only works one way. else, it's bijective!

this means, that T is injective if it maps distinct inputs to distinct outputs

  1. checking injection

    check if 0 is the only vec that gets mapped to 0.

    title: injetivity is equivelent to null space equals equals {0}
    let $T \in L(V,W)$. Then $T$ is injective iff null $T = \{0\}$ 
    

1.0.4 Range and Surjectivity

time to define, range!

title: range AKA image
for $T$ a function from $V$ to $W$, the *range* of $T$ is the subset of $W$ consisting of those vectors that are of the form of $Tv$ for some $v \in V$: 
$$
\textrm{range} \ T = \{Tv: v \in V\}.
$$

just the… normal def of range.

and some examples: - are in 3.18

title: the range is a subspace!
If $T \in L(V,W),$ then range $T$ is a subspace $W$.

and ofc,

title: surjective AKA onto
a function $T: V \to W$ is called *surjective* if its range equals $W$.

surjecitvity depends on the space we are mapping into

1.0.5 Fundemental theorem

this is important! that's why the name is dramatic.

title: Fundemental theorem of linear maps
Suppose $V$ is finite-dimensional $T \in L(V,W).$ Then range $T$ is finite-dimensional and 
$$\dim V = \dim null \ T + \dim range \ T$$

1.0.6

uh..

def of a smaller vec space is one with less a smaller dim

we can say that no linear transformation from a finite-dimensional vec space to a smaller vec space can be injective which makes sense! because you need the repeat elements, otherwise it woudnt be smaller.

title: A map to a smaller dimensinal space is not injective
Suppose $V$ and $W$ are finite-dimensional vector spaces such that $\dim V > \dim W$. Then no linear map from $V$ to $W$ is injective.

#review to make this intuitive.

then we can show that no map from finite-dim vec space to a bigger vec space can be surjective

wait no this one doesnt make sense. cus two elements can map to one, right? #question noo! it doesnt, cus then u would need to have a single function output multiple things to make up for it which functions can't do.

title: A map to a larger dimensional space is not surjective
Suppose $V$ and $W$ are finite-dimensional vector spaces such that $\dim V < \dim W$. Then no linear map from $V$ to $W$ is surjective.

these have imporant conseqneces! in linear equation theory.

idea: express questions about systems of linear equations in terms of linear maps

ie. use linear transformation to represent querys about linear equations

3.25.. what the hell?? #review #question srry i don't have enough brain space to interpret this right now.

title: homogenous system of linear equations
A homogenous system of linear equations with more variables than equations has nonzero solutions.

oh, here, we get to define the concept of free variables

title: Inhomogenous system of linear equations
An inhomogenous system of linear equations with more equations than variables has no solution for some choice of the constant terms.

these can be proved using gaussian elim!

this one needs a reflection! need to watch another vid on the concept of null space and range ect. then take notes on that as well. seek 3b1b for intutive understanding here.